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GCSE Maths Indices Worksheet: Practice Questions by Topic

GCSE Maths Indices Worksheet: Practice Questions by Topic

A repetition-based indices worksheet for GCSE Maths. Each section drills one index law at a time. Work through the sections in order — the aim is confident pattern recognition before tackling mixed questions elsewhere.


How do you multiply indices with the same base?

Rule: am × an = am + n
When the base is the same, add the powers.

Example: m4 × m3 = m4 + 3 = m7

  • (a) m2 × m3
  • (b) m3 × m3
  • (c) m6 × m2
  • (d) m7 × m3
  • (e) m6 × m8
  • (f) m2 × m
  • (g) m × m3
  • (h) m7 × m8
  • (i) m9 × m2
  • (j) m × m8
  • (k) m6 × m5
  • (l) m2 × m2 × m2 × m2
Answers: (a) m5   (b) m6   (c) m8   (d) m10   (e) m14   (f) m3   (g) m4   (h) m15   (i) m11   (j) m9   (k) m11   (l) m8

How do you divide indices with the same base?

Rule: am ÷ an = am − n
When the base is the same, subtract the powers.

Example: n7 ÷ n2 = n7 − 2 = n5

  • (a) n5 ÷ n2
  • (b) n8 ÷ n3
  • (c) n9 ÷ n2
  • (d) n7 ÷ n5
  • (e) n3 ÷ n
  • (f) n8 ÷ n
  • (g) n7 ÷ n4
  • (h) n9 ÷ n3
  • (i) n4 ÷ n8
  • (j) n ÷ n3
  • (k) n45 ÷ n5
  • (l) n3 ÷ n3
Answers: (a) n3   (b) n5   (c) n7   (d) n2   (e) n2   (f) n7   (g) n3   (h) n6   (i) n−4   (j) n−2   (k) n40   (l) 1

How do you raise a power to another power?

Rule: (am)n = am × n
When a power is raised to another power, multiply the powers.

Example: (y4)3 = y4 × 3 = y12

  • (a) (y5)2
  • (b) (y3)2
  • (c) (y4)3
  • (d) (y5)4
  • (e) (y3)6
  • (f) (y7)3
  • (g) (y6)6
  • (h) (y9)2
  • (i) (y4)8
  • (j) (y3)−5
  • (k) (y−5)2
Answers: (a) y10   (b) y6   (c) y12   (d) y20   (e) y18   (f) y21   (g) y36   (h) y18   (i) y32   (j) y−15   (k) y−10

How do you simplify a bracket with a coefficient raised to a power?

Rule: (kam)n = kn × am × n
Apply the outer power to both the number and the letter.

Example: (3x2)3 = 33 × x2 × 3 = 27x6

  • (a) (2x3)2
  • (b) (5x6)2
  • (c) (5x5)3
  • (d) (2x3)4
  • (e) (7x5)2
  • (f) (4x7)3
  • (g) (2x6)6
  • (h) (10x9)3
  • (i) (3x4)4
Answers: (a) 4x6   (b) 25x12   (c) 125x15   (d) 16x12   (e) 49x10   (f) 64x21   (g) 64x36   (h) 1000x27   (i) 81x16

What is any number to the power of 0?

Rule: a0 = 1  (for any non-zero a)
Anything to the power of 0 equals 1.

Example: 60 = 1

  • (a) 50
  • (b) 120
  • (c) x0
  • (d) 1000
  • (e) (−3)0
  • (f) y0
  • (g) 70
  • (h) (2x)0
  • (i) (1/2)0
  • (j) m0
  • (k) (4xy)0
  • (l) 10
Answers: All answers = 1

What does a power of −1 mean?

Rule: a−1 = 1/a
A power of −1 means the reciprocal — flip the number.

Example: 8−1 = 1/8

  • (a) 5−1
  • (b) 2−1
  • (c) 10−1
  • (d) 3−1
  • (e) 7−1
  • (f) 4−1
  • (g) x−1
  • (h) 12−1
  • (i) 100−1
  • (j) (1/2)−1
  • (k) (2/3)−1
  • (l) (3/5)−1
Answers: (a) 1/5   (b) 1/2   (c) 1/10   (d) 1/3   (e) 1/7   (f) 1/4   (g) 1/x   (h) 1/12   (i) 1/100   (j) 2   (k) 3/2   (l) 5/3

What does a power of 1/2 mean?

Rule: a1/2 = √a
A power of 1/2 means the square root.

Example: 251/2 = √25 = 5

  • (a) 91/2
  • (b) 161/2
  • (c) 251/2
  • (d) 361/2
  • (e) 491/2
  • (f) 641/2
  • (g) 811/2
  • (h) 1001/2
  • (i) 1211/2
  • (j) 1441/2
  • (k) 41/2
  • (l) 4001/2
Answers: (a) 3   (b) 4   (c) 5   (d) 6   (e) 7   (f) 8   (g) 9   (h) 10   (i) 11   (j) 12   (k) 2   (l) 20

What does a power of 1/3 mean?

Rule: a1/3 = ³√a
A power of 1/3 means the cube root.

Example: 641/3 = ³√64 = 4

  • (a) 81/3
  • (b) 271/3
  • (c) 641/3
  • (d) 1251/3
  • (e) 10001/3
  • (f) 11/3
  • (g) 2161/3
  • (h) 3431/3
  • (i) 5121/3
  • (j) 7291/3
  • (k) (1/8)1/3
  • (l) (1/27)1/3
Answers: (a) 2   (b) 3   (c) 4   (d) 5   (e) 10   (f) 1   (g) 6   (h) 7   (i) 8   (j) 9   (k) 1/2   (l) 1/3

How do you evaluate a power of 3/2 or 2/3?

Rule: am/n = (n√a)m
Do the root first (from the denominator), then the power (from the numerator). Rooting first keeps the numbers small.

Example: 82/3 = (³√8)2 = 22 = 4

Part 1 — powers of 3/2:

  • (a) 43/2
  • (b) 93/2
  • (c) 163/2
  • (d) 253/2
  • (e) 363/2
  • (f) 1003/2

Part 2 — powers of 2/3:

  • (g) 82/3
  • (h) 272/3
  • (i) 642/3
  • (j) 1252/3
  • (k) 10002/3
  • (l) 2162/3
Answers: (a) 8   (b) 27   (c) 64   (d) 125   (e) 216   (f) 1000   (g) 4   (h) 9   (i) 16   (j) 25   (k) 100   (l) 36

How do you evaluate negative fractional indices?

Rule: a−m/n = 1 / am/n
The minus sign makes it a reciprocal. Then evaluate the fractional power as before: root first, then power.

Example: 9−1/2 = 1 / 91/2 = 1/3

  • (a) 4−1/2
  • (b) 9−1/2
  • (c) 16−1/2
  • (d) 25−1/2
  • (e) 8−1/3
  • (f) 27−1/3
  • (g) 64−1/3
  • (h) 125−1/3
  • (i) 4−3/2
  • (j) 9−3/2
  • (k) 8−2/3
  • (l) 27−2/3
Answers: (a) 1/2   (b) 1/3   (c) 1/4   (d) 1/5   (e) 1/2   (f) 1/3   (g) 1/4   (h) 1/5   (i) 1/8   (j) 1/27   (k) 1/4   (l) 1/9

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